Now we've had a gentle introduction to abstract mathematics with groups, we're ready to explore a slightly more complex structure: Fields.
Just like groups, fields have a set of elements that can be combined. However, this time they can be combined with not one, but two operations. One operation, , behaves like multiplication and the other, , behaves like addition.
These two operations must obey the following properties:
Very simple one we already saw in groups. Combining any 2 elements from the field under any operation should produce another member of the field.
Another one we've seen already from groups. The brackets must behave the same way with both operations.
There must exist an additive and multiplicative identity in the field. The elements and are the additive and multiplicative identities, respectively. The decision to label them as and is arbitrary, but it is a common convention.
Every element must have both an additive and multiplicative inverse. The elements and are the additive and multiplicative inverses, respectively. Again the decision to label them as such is arbitrary, but a common convention.
Note the special case defined here for multiplication. The additive inverse doesn't need to have a multiplicative inverse. This makes sense becase there's nothing we can multiply by 0 to get 1.
We should get the same result from either operation even when we swap the order of the elements.
Remeber that this wasn't a strict requirement for groups, but it will be in fields.
This is a completely new rule that we didn't have with groups. This tells us how the 2 operations interact when used together.
Now we've defined our rules. Let's take a look at an example of a field!
This is like the set of integers, but with a twist. We only care about the remainders when divided by 3. So, we have the following elements:
We can think about this as counting on a clock with 3 hours, starting from 0:
Say we want to check what is. Normally,, but we don't have 4 in our set of elements. So we'll need another way to think about addition.
With normal addition, to calculate , we'd point to the number on the number line and then move 2 places further along. Let's do that but using our clock:
So in our field, ! Earlier we said the elements of our field were the integers remainder when divided by 3, so this result makes sense since 4 divided by 3 gives a remainder of 1. This gives us another way to calculate results here. Instead of using the clock, we can just do the calculation on the normal number line and then take the remainder of the result when divided by 3.
And multiplication just behaves as we would expect. Let's draw out the addition and multiplication tables:
So does this satisfy our rules? Let's check!
So we've proved that is a valid field!
Although we have only a few rules on fields, there are actually many interesting properties that we can prove from these rules. We'll do one example here to give a flavour and then leave some more to the exercises.
One of the things we know from basic maths is that if then either or . Here's how we can prove this using the rules above:
We'll do a proof by contradiction. We'll assume the opposite is true and then show that it implies a contradiction. So we'll assume and . Then we have:
Since we know it must have a multiplicative inverse so we can multiply both sides by it to get:
This violates our assumption! An equivalent argument could be made for . So we have proved our statement!
Move on to the exercises to see if you can prove some more interesting facts!
Prove that
Seems fairly obvious in normal math, but requires careful proof when we're dealing with more abstract objects.
Prove that .
Note here the usage of the term . Fields are abstract so don't have to represent numbers. What we're actually describing here is the additive inverse of the multiplicative identity. The notation is just for convenience.
Prove that, for our field, that following holds: where we define . Note here I'm leaving out the brackets for simplicity.
There are 2 ways to prove this. You can check every possible combination, or you can use the rules we defined. See if you can find both proofs.